What are the solutions to the equation u^2+10u+25=0 ?

The solutions to the equation u^2+10u+25=0 are u=-5

Find the zeros of u^2+10u+25=0

The zeros of u^2+10u+25=0 are u=-5

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u^{2} + 10 u + 25 = 0

u = - 5

Solution steps

u^{2} + 10 u + 25 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

u_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

u = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

u = - 5

The solution to the quadratic equation is:

u = - 5

(p + 1) (p + 3) = 0

12 x^{2} = 17 x + 5

\frac{16 i ^{2}}{2 i}

(x - 2)^{4}

15 h^{2} - 17 h - 4

What are the solutions to the equation u^2+10u+25=0 ?
The solutions to the equation u^2+10u+25=0 are u=-5
Find the zeros of u^2+10u+25=0
The zeros of u^2+10u+25=0 are u=-5