What is ((2a^2b)^2)/((-2a^2b^3)^2) ?

The solution to ((2a^2b)^2)/((-2a^2b^3)^2) is 1/(b^4)

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simplify ((2a^2b)^2)/((-2a^2b^3)^2)

simplify

\frac{( 2 a ^{2} b ) ^{2}}{( - 2 a ^{2} b ^{3} ) ^{2}}

\frac{1}{b ^{4}}

Solution steps

\frac{( 2 a ^{2} b ) ^{2}}{( - 2 a ^{2} b ^{3} ) ^{2}}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2 a^{2} b^{3})^{2} = (2 a^{2} b^{3})^{2}

= \frac{( 2 a ^{2} b ) ^{2}}{( 2 a ^{2} b ^{3} ) ^{2}}

Simplify

(2 a^{2} b)^{2} : 2^{2} a^{4} b^{2}

= \frac{2 ^{2} a ^{4} b ^{2}}{( 2 a ^{2} b ^{3} ) ^{2}}

Simplify

(2 a^{2} b^{3})^{2} : 2^{2} a^{4} b^{6}

= \frac{2 ^{2} a ^{4} b ^{2}}{2 ^{2} a ^{4} b ^{6}}

Cancel the common factor:

2^{2}

= \frac{a ^{4} b ^{2}}{a ^{4} b ^{6}}

Cancel the common factor:

a^{4}

= \frac{b ^{2}}{b ^{6}}

Simplify

\frac{b ^{2}}{b ^{6}} : \frac{1}{b ^{4}}

= \frac{1}{b ^{4}}

3 (x + 1) = 5 (x - 2) + 7

0 = x^{2} + 9 x - 36

(- 3 x^{3} y^{5})^{3}

2 x^{2} + x y - y^{2}

- x < 4

What is ((2a^2b)^2)/((-2a^2b^3)^2) ?
The solution to ((2a^2b)^2)/((-2a^2b^3)^2) is 1/(b^4)