What is (2/(b^3))b^{-3} ?

The solution to (2/(b^3))b^{-3} is 2/(b^6)

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simplify (2/(b^3))b^{-3}

simplify

(\frac{2}{b ^{3}}) b^{- 3}

\frac{2}{b ^{6}}

Solution steps

(\frac{2}{b ^{3}}) b^{- 3}

Apply rule:

(a) = a

(\frac{2}{b ^{3}}) = \frac{2}{b ^{3}}

= \frac{2}{b ^{3}} b^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

b^{- 3} = \frac{1}{b ^{3}}

= \frac{2}{b ^{3}} \cdot \frac{1}{b ^{3}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{2 \cdot 1}{b ^{3} b ^{3}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2}{b ^{3} b ^{3}}

Simplify

b^{3} b^{3} : b^{6}

= \frac{2}{b ^{6}}

3 x^{2} - 6 x - 11 = 0

\frac{10 - 4 x}{2 x - 5} \geq 4 x - 1

x^{2} + 4 x + 21 = 42

9 (3 x + 9) + (x + 3) = 14

\frac{\frac{2 x + y}{36}}{\frac{36 + 36 x - 7 x ^{2}}{288}}