What is factor b^6-64 ?

The solution to factor b^6-64 is (b+2)(b-2)(b^2+4+2b)(b^2+4-2b)

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factor b^6-64

factor

b^{6} - 64

(b + 2) (b - 2) (b^{2} + 4 + 2 b) (b^{2} + 4 - 2 b)

Solution steps

b^{6} - 64

Apply exponent rules

= (b^{2})^{3} - 4^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(b^{2})^{3} - 4^{3} = (b^{2} - 4) (b^{4} + 4 b^{2} + 4^{2})

= (b^{2} - 4) (b^{4} + 4 b^{2} + 4^{2})

Factor

b^{2} - 4 : (b + 2) (b - 2)

= (b + 2) (b - 2) (b^{4} + 4 b^{2} + 4^{2})

Factor

b^{4} + 4 b^{2} + 4^{2} : (b^{2} + 4 + 2 b) (b^{2} + 4 - 2 b)

= (b + 2) (b - 2) (b^{2} + 4 + 2 b) (b^{2} + 4 - 2 b)

i^{- 55}

\frac{1}{2} (20 x + 6) \geq x + 30

x^{2} + 5 x + 9 = 0

3 x^{3} - 6 x^{2} - 45 x

lo g_{4} (2 x + 5) \leq lo g_{4} (4 x - 3)

What is factor b^6-64 ?
The solution to factor b^6-64 is (b+2)(b-2)(b^2+4+2b)(b^2+4-2b)