What are the solutions to the equation 2(x-8)^2+40=16 ?

The solutions to the equation 2(x-8)^2+40=16 are x=2sqrt(3)i+8,x=-2sqrt(3)i+8

Find the zeros of 2(x-8)^2+40=16

The zeros of 2(x-8)^2+40=16 are x=2sqrt(3)i+8,x=-2sqrt(3)i+8

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2 (x - 8)^{2} + 40 = 16

x = 23 i + 8, x = - 23 i + 8

Solution steps

2 (x - 8)^{2} + 40 = 16

Move

40

to the right side

2 (x - 8)^{2} = - 24

Divide both sides by

2

(x - 8)^{2} = - 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 8 = - 12 : x = 23 i + 8

Solve

x - 8 = - - 12 : x = - 23 i + 8

The solutions to the quadratic equation are:

x = 23 i + 8, x = - 23 i + 8

\frac{5}{4} + \frac{1}{2}

3 x^{2} + 12 x - 6 = 0

x^{5} + 6 x^{4} y + 9 x^{3} y^{2} + x^{2} y^{3} + 6 x y^{4} + 9 y^{5}

\frac{11 + 3}{11 - 3}

x^{4} + 16 x^{2}

What are the solutions to the equation 2(x-8)^2+40=16 ?
The solutions to the equation 2(x-8)^2+40=16 are x=2sqrt(3)i+8,x=-2sqrt(3)i+8
Find the zeros of 2(x-8)^2+40=16
The zeros of 2(x-8)^2+40=16 are x=2sqrt(3)i+8,x=-2sqrt(3)i+8