What are the solutions to the equation x^2+4x+4=9 ?

The solutions to the equation x^2+4x+4=9 are x=1,x=-5

Find the zeros of x^2+4x+4=9

The zeros of x^2+4x+4=9 are x=1,x=-5

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x^{2} + 4 x + 4 = 9

x = 1, x = - 5

Solution steps

x^{2} + 4 x + 4 = 9

Move

9

to the left side

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

- 2 + 3 x + 3 < 7

6 x^{2} + 7 x + 2 = 0

x^{- \frac{1}{4}}

(A^{1 + \frac{x}{y}})^{\frac{y}{x + y}}

lo g_{7} (49)

What are the solutions to the equation x^2+4x+4=9 ?
The solutions to the equation x^2+4x+4=9 are x=1,x=-5
Find the zeros of x^2+4x+4=9
The zeros of x^2+4x+4=9 are x=1,x=-5