What are the solutions to the equation 6x^2-2x-2=0 ?

The solutions to the equation 6x^2-2x-2=0 are x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

Find the zeros of 6x^2-2x-2=0

The zeros of 6x^2-2x-2=0 are x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6

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6 x^{2} - 2 x - 2 = 0

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

Decimal Notation

x = 0.76759 \dots, x = - 0.43425 \dots

Solution steps

6 x^{2} - 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 2)^{2} - 4 \cdot 6 (- 2) = 213

x_{1, 2} = \frac{- ( - 2 ) \pm 2 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 13}{2 \cdot 6}, x_{2} = \frac{- ( - 2 ) - 2 13}{2 \cdot 6}

x = \frac{- ( - 2 ) + 2 13}{2 \cdot 6} : \frac{1 + 13}{6}

x = \frac{- ( - 2 ) - 2 13}{2 \cdot 6} : \frac{1 - 13}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{6}, x = \frac{1 - 13}{6}

x^{- \frac{1}{2}} \cdot x^{- 1}

x^{3} - x^{2} z + x y - yz

5 w^{2} = - 26 w - 5

n^{3} + 2 n^{2} - 4 n - 8

\frac{x + 5}{3} = 2

What are the solutions to the equation 6x^2-2x-2=0 ?
The solutions to the equation 6x^2-2x-2=0 are x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6
Find the zeros of 6x^2-2x-2=0
The zeros of 6x^2-2x-2=0 are x=(1+sqrt(13))/6 ,x=(1-sqrt(13))/6