What are the solutions to the equation x^2-x+3=3 ?

The solutions to the equation x^2-x+3=3 are x=1,x=0

Find the zeros of x^2-x+3=3

The zeros of x^2-x+3=3 are x=1,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x + 3 = 3

x = 1, x = 0

Solution steps

x^{2} - x + 3 = 3

Move

3

to the left side

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

x^{2} - 4 x = 60

5 n - 11 < - 4.4 + 2 n

\frac{5 a ^{2} - 9 a - 2}{a ^{2} + 4 a - 12}

\frac{304 + 2 x}{6} \geq 70

(\frac{5}{9})^{- 1}

What are the solutions to the equation x^2-x+3=3 ?
The solutions to the equation x^2-x+3=3 are x=1,x=0
Find the zeros of x^2-x+3=3
The zeros of x^2-x+3=3 are x=1,x=0