What are the solutions to the equation 3s^2+8s=2s-9 ?

The solutions to the equation 3s^2+8s=2s-9 are s=-1+sqrt(2)i,s=-1-sqrt(2)i

Find the zeros of 3s^2+8s=2s-9

The zeros of 3s^2+8s=2s-9 are s=-1+sqrt(2)i,s=-1-sqrt(2)i

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3 s^{2} + 8 s = 2 s - 9

s = - 1 + 2 i, s = - 1 - 2 i

Solution steps

3 s^{2} + 8 s = 2 s - 9

Move

9

to the left side

3 s^{2} + 8 s + 9 = 2 s

Move

2 s

to the left side

3 s^{2} + 6 s + 9 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

6^{2} - 4 \cdot 3 \cdot 9 : 62 i

s_{1, 2} = \frac{- 6 \pm 6 2 i}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 6 + 6 2 i}{2 \cdot 3}, s_{2} = \frac{- 6 - 6 2 i}{2 \cdot 3}

s = \frac{- 6 + 6 2 i}{2 \cdot 3} : - 1 + 2 i

s = \frac{- 6 - 6 2 i}{2 \cdot 3} : - 1 - 2 i

The solutions to the quadratic equation are:

s = - 1 + 2 i, s = - 1 - 2 i

x^{2} - 6 x + 36 = 0

3 x + 4 = 6

12 x y^{5} + 60 x^{4} y^{2} - 24 x^{3} y^{3}

\frac{5}{3} x + \frac{3}{4} < \frac{2}{5}

e^{- \frac{x ^{2}}{2}}

What are the solutions to the equation 3s^2+8s=2s-9 ?
The solutions to the equation 3s^2+8s=2s-9 are s=-1+sqrt(2)i,s=-1-sqrt(2)i
Find the zeros of 3s^2+8s=2s-9
The zeros of 3s^2+8s=2s-9 are s=-1+sqrt(2)i,s=-1-sqrt(2)i