What are the solutions to the equation w^2-3w-40=0 ?

The solutions to the equation w^2-3w-40=0 are w=8,w=-5

Find the zeros of w^2-3w-40=0

The zeros of w^2-3w-40=0 are w=8,w=-5

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w^{2} - 3 w - 40 = 0

w = 8, w = - 5

Solution steps

w^{2} - 3 w - 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

w_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, w_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

w = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

w = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

w = 8, w = - 5

3 x - (x - 5) = 9

y^{2} + 20 y + 84 = 0

\frac{x - 1}{1 + x} > - 2

(- \frac{4}{3})^{- 6}

2 (9)^{\frac{3}{2}}

What are the solutions to the equation w^2-3w-40=0 ?
The solutions to the equation w^2-3w-40=0 are w=8,w=-5
Find the zeros of w^2-3w-40=0
The zeros of w^2-3w-40=0 are w=8,w=-5