What are the solutions to the equation y^2+20y+84=0 ?

The solutions to the equation y^2+20y+84=0 are y=-6,y=-14

Find the zeros of y^2+20y+84=0

The zeros of y^2+20y+84=0 are y=-6,y=-14

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y^{2} + 20 y + 84 = 0

y = - 6, y = - 14

Solution steps

y^{2} + 20 y + 84 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 84}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 84 = 8

y_{1, 2} = \frac{- 20 \pm 8}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 20 + 8}{2 \cdot 1}, y_{2} = \frac{- 20 - 8}{2 \cdot 1}

y = \frac{- 20 + 8}{2 \cdot 1} : - 6

y = \frac{- 20 - 8}{2 \cdot 1} : - 14

The solutions to the quadratic equation are:

y = - 6, y = - 14

\frac{x - 1}{1 + x} > - 2

(- \frac{4}{3})^{- 6}

2 (9)^{\frac{3}{2}}

4 e + 6 - 11 e = - 8

120 = (x - 14) (x - 6) 0.5

What are the solutions to the equation y^2+20y+84=0 ?
The solutions to the equation y^2+20y+84=0 are y=-6,y=-14
Find the zeros of y^2+20y+84=0
The zeros of y^2+20y+84=0 are y=-6,y=-14