What are the solutions to the equation y^2-9y-10=0 ?

The solutions to the equation y^2-9y-10=0 are y=10,y=-1

Find the zeros of y^2-9y-10=0

The zeros of y^2-9y-10=0 are y=10,y=-1

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y^{2} - 9 y - 10 = 0

y = 10, y = - 1

Solution steps

y^{2} - 9 y - 10 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 10) = 11

y_{1, 2} = \frac{- ( - 9 ) \pm 11}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 9 ) + 11}{2 \cdot 1}, y_{2} = \frac{- ( - 9 ) - 11}{2 \cdot 1}

y = \frac{- ( - 9 ) + 11}{2 \cdot 1} : 10

y = \frac{- ( - 9 ) - 11}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

y = 10, y = - 1

x^{2} + 5 x + (\frac{5}{2})^{2} = 0

v p + 12 v + 8 p + 96

\frac{3}{2} 6

4 (x + 3) < 3 x + 7

What are the solutions to the equation y^2-9y-10=0 ?
The solutions to the equation y^2-9y-10=0 are y=10,y=-1
Find the zeros of y^2-9y-10=0
The zeros of y^2-9y-10=0 are y=10,y=-1