What are the solutions to the equation (c+9)^2=64 ?

The solutions to the equation (c+9)^2=64 are c=-1,c=-17

Find the zeros of (c+9)^2=64

The zeros of (c+9)^2=64 are c=-1,c=-17

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(c + 9)^{2} = 64

c = - 1, c = - 17

Solution steps

(c + 9)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

c + 9 = 64 : c = - 1

Solve

c + 9 = - 64 : c = - 17

The solutions to the quadratic equation are:

c = - 1, c = - 17

4 (u + 1) - 7 = 3 (u - 1) + u

1 + 64 y^{3}

4 x^{3} - 64 x

\frac{1}{3} u^{2} + \frac{2}{3} u = - \frac{1}{12}

(5 - 4 i)^{2}

What are the solutions to the equation (c+9)^2=64 ?
The solutions to the equation (c+9)^2=64 are c=-1,c=-17
Find the zeros of (c+9)^2=64
The zeros of (c+9)^2=64 are c=-1,c=-17