What are the solutions to the equation 3x^2-9=-18x ?

The solutions to the equation 3x^2-9=-18x are x=-3+2sqrt(3),x=-3-2sqrt(3)

Find the zeros of 3x^2-9=-18x

The zeros of 3x^2-9=-18x are x=-3+2sqrt(3),x=-3-2sqrt(3)

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3 x^{2} - 9 = - 18 x

x = - 3 + 23, x = - 3 - 23

Decimal Notation

x = 0.46410 \dots, x = - 6.46410 \dots

Solution steps

3 x^{2} - 9 = - 18 x

Move

18 x

to the left side

3 x^{2} - 9 + 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} + 18 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

1 8^{2} - 4 \cdot 3 (- 9) = 123

x_{1, 2} = \frac{- 18 \pm 12 3}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 18 + 12 3}{2 \cdot 3}, x_{2} = \frac{- 18 - 12 3}{2 \cdot 3}

x = \frac{- 18 + 12 3}{2 \cdot 3} : - 3 + 23

x = \frac{- 18 - 12 3}{2 \cdot 3} : - 3 - 23

The solutions to the quadratic equation are:

x = - 3 + 23, x = - 3 - 23

(2 y + 1) (3 y + 1) = (6 y - 1) (y + 2)

- \frac{10}{4}

2 x^{2} + 8 x - 960

∣ x - 2 ∣ \leq 9

\frac{( - 3 x ^{2} + 1400 x )}{x}

What are the solutions to the equation 3x^2-9=-18x ?
The solutions to the equation 3x^2-9=-18x are x=-3+2sqrt(3),x=-3-2sqrt(3)
Find the zeros of 3x^2-9=-18x
The zeros of 3x^2-9=-18x are x=-3+2sqrt(3),x=-3-2sqrt(3)