What are the solutions to the equation x^2+3x+12=0 ?

The solutions to the equation x^2+3x+12=0 are x=-3/2+i(sqrt(39))/2 ,x=-3/2-i(sqrt(39))/2

Find the zeros of x^2+3x+12=0

The zeros of x^2+3x+12=0 are x=-3/2+i(sqrt(39))/2 ,x=-3/2-i(sqrt(39))/2

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x^{2} + 3 x + 12 = 0

x = - \frac{3}{2} + i \frac{39}{2}, x = - \frac{3}{2} - i \frac{39}{2}

Solution steps

x^{2} + 3 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 12 : 39 i

x_{1, 2} = \frac{- 3 \pm 39 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 39 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 39 i}{2 \cdot 1}

x = \frac{- 3 + 39 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{39}{2}

x = \frac{- 3 - 39 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{39}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{39}{2}, x = - \frac{3}{2} - i \frac{39}{2}

(- 5)^{3}

ln^{2} (1)

3 + (3 - 2 x)^{2} = 12

(2 p - 1)^{2} - 3 = (p - 2) (p - 1)

\frac{16 π}{7} - 2 π

What are the solutions to the equation x^2+3x+12=0 ?
The solutions to the equation x^2+3x+12=0 are x=-3/2+i(sqrt(39))/2 ,x=-3/2-i(sqrt(39))/2
Find the zeros of x^2+3x+12=0
The zeros of x^2+3x+12=0 are x=-3/2+i(sqrt(39))/2 ,x=-3/2-i(sqrt(39))/2