What are the solutions to the equation 36x^2+24x-24=0 ?

The solutions to the equation 36x^2+24x-24=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

Find the zeros of 36x^2+24x-24=0

The zeros of 36x^2+24x-24=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3

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36 x^{2} + 24 x - 24 = 0

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

Decimal

x = 0.54858 \dots, x = - 1.21525 \dots

Solution steps

36 x^{2} + 24 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 36 ( - 24 )}{2 \cdot 36}

2 4^{2} - 4 \cdot 36 (- 24) = 247

x_{1, 2} = \frac{- 24 \pm 24 7}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- 24 + 24 7}{2 \cdot 36}, x_{2} = \frac{- 24 - 24 7}{2 \cdot 36}

x = \frac{- 24 + 24 7}{2 \cdot 36} : \frac{- 1 + 7}{3}

x = \frac{- 24 - 24 7}{2 \cdot 36} : - \frac{1 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 7}{3}, x = - \frac{1 + 7}{3}

6 n^{2} - 11 n - 10

∣ x ∣ < 14

(x - 3)^{2} + 2

x^{2} + 4 x - 94 = 0

\frac{7}{4 2}

What are the solutions to the equation 36x^2+24x-24=0 ?
The solutions to the equation 36x^2+24x-24=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3
Find the zeros of 36x^2+24x-24=0
The zeros of 36x^2+24x-24=0 are x=(-1+sqrt(7))/3 ,x=-(1+sqrt(7))/3