What are the solutions to the equation (8+2x)(26+2x)=448 ?

The solutions to the equation (8+2x)(26+2x)=448 are x=3,x=-20

Find the zeros of (8+2x)(26+2x)=448

The zeros of (8+2x)(26+2x)=448 are x=3,x=-20

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(8 + 2 x) (26 + 2 x) = 448

x = 3, x = - 20

Solution steps

(8 + 2 x) (26 + 2 x) = 448

Expand

(8 + 2 x) (26 + 2 x) : 208 + 68 x + 4 x^{2}

208 + 68 x + 4 x^{2} = 448

Move

448

to the left side

4 x^{2} + 68 x - 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 68 \pm 6 8 ^{2} - 4 \cdot 4 ( - 240 )}{2 \cdot 4}

6 8^{2} - 4 \cdot 4 (- 240) = 92

x_{1, 2} = \frac{- 68 \pm 92}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 68 + 92}{2 \cdot 4}, x_{2} = \frac{- 68 - 92}{2 \cdot 4}

x = \frac{- 68 + 92}{2 \cdot 4} : 3

x = \frac{- 68 - 92}{2 \cdot 4} : - 20

The solutions to the quadratic equation are:

x = 3, x = - 20

\frac{4}{5 - 3}

\frac{5 x + 1}{2} = 4 x - 7

a^{4} b^{4} - 2 a^{2} b^{2} - 99

∣ 4 (x - 1) + 2 ∣ \leq 22

\frac{18 !}{9 ! \cdot 9 !}

What are the solutions to the equation (8+2x)(26+2x)=448 ?
The solutions to the equation (8+2x)(26+2x)=448 are x=3,x=-20
Find the zeros of (8+2x)(26+2x)=448
The zeros of (8+2x)(26+2x)=448 are x=3,x=-20