What are the solutions to the equation 10b^2-27b+18=0 ?

The solutions to the equation 10b^2-27b+18=0 are b= 3/2 ,b= 6/5

Find the zeros of 10b^2-27b+18=0

The zeros of 10b^2-27b+18=0 are b= 3/2 ,b= 6/5

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10 b^{2} - 27 b + 18 = 0

b = \frac{3}{2}, b = \frac{6}{5}

Decimal Notation

b = 1.5, b = 1.2

Solution steps

10 b^{2} - 27 b + 18 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 10 \cdot 18}{2 \cdot 10}

(- 27)^{2} - 4 \cdot 10 \cdot 18 = 3

b_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 \cdot 10}

Separate the solutions

b_{1} = \frac{- ( - 27 ) + 3}{2 \cdot 10}, b_{2} = \frac{- ( - 27 ) - 3}{2 \cdot 10}

b = \frac{- ( - 27 ) + 3}{2 \cdot 10} : \frac{3}{2}

b = \frac{- ( - 27 ) - 3}{2 \cdot 10} : \frac{6}{5}

The solutions to the quadratic equation are:

b = \frac{3}{2}, b = \frac{6}{5}

- 4 i^{2} + 2 i

10 (x + 1) = 5 (2 x + 2)

1 = (x - 2)^{2}

\frac{1.9864 \cdot 1 0 ^{- 25}}{4 \cdot 1 0 ^{- 7}}

\frac{m}{3} + 4 = 21

What are the solutions to the equation 10b^2-27b+18=0 ?
The solutions to the equation 10b^2-27b+18=0 are b= 3/2 ,b= 6/5
Find the zeros of 10b^2-27b+18=0
The zeros of 10b^2-27b+18=0 are b= 3/2 ,b= 6/5