What are the solutions to the equation x+3=(x-1)(x+2) ?

The solutions to the equation x+3=(x-1)(x+2) are x=sqrt(5),x=-sqrt(5)

Find the zeros of x+3=(x-1)(x+2)

The zeros of x+3=(x-1)(x+2) are x=sqrt(5),x=-sqrt(5)

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x + 3 = (x - 1) (x + 2)

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

x + 3 = (x - 1) (x + 2)

Expand

(x - 1) (x + 2) : x^{2} + x - 2

x + 3 = x^{2} + x - 2

Switch sides

x^{2} + x - 2 = x + 3

Move

2

to the right side

x^{2} + x = x + 5

Move

x

to the left side

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

t^{2} - 23 t = 0

8 m^{2} + 30 m + 7

\frac{6}{8}

- 6 < 5 x + 4 \leq 11

- \frac{3}{4} + \frac{1}{2}

What are the solutions to the equation x+3=(x-1)(x+2) ?
The solutions to the equation x+3=(x-1)(x+2) are x=sqrt(5),x=-sqrt(5)
Find the zeros of x+3=(x-1)(x+2)
The zeros of x+3=(x-1)(x+2) are x=sqrt(5),x=-sqrt(5)