What is the answer to 1100t=(0.9)/(1+20e^{-2.25)} ?

The answer to 1100t=(0.9)/(1+20e^{-2.25)} is t=(0.9e^{2.25})/(1100(e^{2.25)+20)}

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1100t=(0.9)/(1+20e^{-2.25)}

1100 t = \frac{0.9}{1 + 20 e ^{- 2.25}}

t = \frac{0.9 e ^{2.25}}{1100 ( e ^{2.25} + 20 )}

Decimal Notation

t = 0.00026 \dots

Solution steps

1100 t = \frac{0.9}{1 + 20 e ^{- 2.25}}

Simplify

\frac{0.9}{1 + 20 e ^{- 2.25}} : \frac{0.9}{1 + \frac{20}{e ^{2.25}}}

1100 t = \frac{0.9}{1 + \frac{20}{e ^{2.25}}}

Divide both sides by

1100

t = \frac{0.9 e ^{2.25}}{1100 ( e ^{2.25} + 20 )}

\frac{1 + i}{2 - i} + \frac{- 3 - 2 i}{1 + 3 i}

∣ 2 x - 2 ∣ = ∣ - 6 ∣

3 - 3 i

x^{3} - 27 x + 54

\frac{p + q}{p - q} - 2

What is the answer to 1100t=(0.9)/(1+20e^{-2.25)} ?
The answer to 1100t=(0.9)/(1+20e^{-2.25)} is t=(0.9e^{2.25})/(1100(e^{2.25)+20)}