What are the solutions to the equation 12x^2+29x-8=0 ?

The solutions to the equation 12x^2+29x-8=0 are x= 1/4 ,x=-8/3

Find the zeros of 12x^2+29x-8=0

The zeros of 12x^2+29x-8=0 are x= 1/4 ,x=-8/3

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12 x^{2} + 29 x - 8 = 0

x = \frac{1}{4}, x = - \frac{8}{3}

Decimal Notation

x = 0.25, x = - 2.66666 \dots

Solution steps

12 x^{2} + 29 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 12 ( - 8 )}{2 \cdot 12}

2 9^{2} - 4 \cdot 12 (- 8) = 35

x_{1, 2} = \frac{- 29 \pm 35}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 29 + 35}{2 \cdot 12}, x_{2} = \frac{- 29 - 35}{2 \cdot 12}

x = \frac{- 29 + 35}{2 \cdot 12} : \frac{1}{4}

x = \frac{- 29 - 35}{2 \cdot 12} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{8}{3}

2 x^{2} + 14 x + 24

2 - (- 10 q - 4) \geq - 8 q + 6 - 10 q

27 a^{3} - 64 b^{3}

2 x^{2} + 5 x + 12 = 0

8 x^{2} - 9 x + 1

What are the solutions to the equation 12x^2+29x-8=0 ?
The solutions to the equation 12x^2+29x-8=0 are x= 1/4 ,x=-8/3
Find the zeros of 12x^2+29x-8=0
The zeros of 12x^2+29x-8=0 are x= 1/4 ,x=-8/3