What are the solutions to the equation -2x^2+5=0 ?

The solutions to the equation -2x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of -2x^2+5=0

The zeros of -2x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2)

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- 2 x^{2} + 5 = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

- 2 x^{2} + 5 = 0

Move

5

to the right side

- 2 x^{2} = - 5

Divide both sides by

- 2

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

\frac{x + 8}{x - 1} \geq - 2

- 5 \cdot 20

2 (x - 5) + 3 x = 20

8 c^{2} = 4 c

4 (\frac{1}{6}) (\frac{5}{6})^{3}

What are the solutions to the equation -2x^2+5=0 ?
The solutions to the equation -2x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of -2x^2+5=0
The zeros of -2x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2)