What are the solutions to the equation 8c^2=4c ?

The solutions to the equation 8c^2=4c are c=0,c= 1/2

Find the zeros of 8c^2=4c

The zeros of 8c^2=4c are c=0,c= 1/2

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8 c^{2} = 4 c

c = 0, c = \frac{1}{2}

Decimal Notation

c = 0, c = 0.5

Solution steps

8 c^{2} = 4 c

Move

4 c

to the left side

8 c^{2} - 4 c = 0

Factor

8 c^{2} - 4 c : 4 c (2 c - 1)

4 c (2 c - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

c = 0 or 2 c - 1 = 0

Solve

2 c - 1 = 0 : c = \frac{1}{2}

The solutions to the quadratic equation are:

c = 0, c = \frac{1}{2}

4 (\frac{1}{6}) (\frac{5}{6})^{3}

(4 c^{- 3} d^{- 3}) (- 7 c^{- 3} d)

\frac{11}{12} - \frac{3}{8}

\frac{a ^{3} b ^{3} c ^{5}}{a b ^{6} c ^{2}}

x^{2} + 6 x + 9 = 25

What are the solutions to the equation 8c^2=4c ?
The solutions to the equation 8c^2=4c are c=0,c= 1/2
Find the zeros of 8c^2=4c
The zeros of 8c^2=4c are c=0,c= 1/2