What is factor x^4y^2-1 ?

The solution to factor x^4y^2-1 is (x^2y+1)(x^2y-1)

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factor x^4y^2-1

factor

x^{4} y^{2} - 1

(x^{2} y + 1) (x^{2} y - 1)

Solution steps

x^{4} y^{2} - 1

x^{4} y^{2} = (x^{2} y)^{2}

1 = 1^{2}

= (x^{2} y)^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(x^{2} y)^{2} - 1^{2} = (x^{2} y + 1) (x^{2} y - 1)

= (x^{2} y + 1) (x^{2} y - 1)

f = ((0.5)^{3} - 0. 5^{2} + 4 (0.5) - 3)

6 - (- 2)

(7 x - 2)^{2} - 3 (7 x - 2) - 2 = 0

36 x^{2} - 48 x + 16 = 0

\frac{a ^{- 1} + 2}{a ^{- 1} - 2}