What are the solutions to the equation 2x+x^2=7x ?

The solutions to the equation 2x+x^2=7x are x=5,x=0

Find the zeros of 2x+x^2=7x

The zeros of 2x+x^2=7x are x=5,x=0

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2 x + x^{2} = 7 x

x = 5, x = 0

Solution steps

2 x + x^{2} = 7 x

Move

7 x

to the left side

x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

(x + 6) (x - 2) = - 7

98 x - 49 x^{2} - 45

6 a^{2} - 7 ab - 3 b^{2}

4 (y - 3) - 6 y = - 2 (y + 6)

- 3 x^{2} - x + 2

What are the solutions to the equation 2x+x^2=7x ?
The solutions to the equation 2x+x^2=7x are x=5,x=0
Find the zeros of 2x+x^2=7x
The zeros of 2x+x^2=7x are x=5,x=0