What are the solutions to the equation x^2+8x-4=10 ?

The solutions to the equation x^2+8x-4=10 are x=-4+sqrt(30),x=-4-sqrt(30)

Find the zeros of x^2+8x-4=10

The zeros of x^2+8x-4=10 are x=-4+sqrt(30),x=-4-sqrt(30)

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x^{2} + 8 x - 4 = 10

x = - 4 + 30, x = - 4 - 30

Decimal Notation

x = 1.47722 \dots, x = - 9.47722 \dots

Solution steps

x^{2} + 8 x - 4 = 10

Move

10

to the left side

x^{2} + 8 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 14) = 230

x_{1, 2} = \frac{- 8 \pm 2 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 30}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 30}{2 \cdot 1}

x = \frac{- 8 + 2 30}{2 \cdot 1} : - 4 + 30

x = \frac{- 8 - 2 30}{2 \cdot 1} : - 4 - 30

The solutions to the quadratic equation are:

x = - 4 + 30, x = - 4 - 30

100 x^{2} + 1 = 12 x

\frac{5}{4} - \frac{27}{2}

- 16 x^{2} + 64 x + 80

27 \cdot 6

x^{2} + 7 x - 18

What are the solutions to the equation x^2+8x-4=10 ?
The solutions to the equation x^2+8x-4=10 are x=-4+sqrt(30),x=-4-sqrt(30)
Find the zeros of x^2+8x-4=10
The zeros of x^2+8x-4=10 are x=-4+sqrt(30),x=-4-sqrt(30)