What are the solutions to the equation 25x^2+60x=-36 ?

The solutions to the equation 25x^2+60x=-36 are x=-6/5

Find the zeros of 25x^2+60x=-36

The zeros of 25x^2+60x=-36 are x=-6/5

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25 x^{2} + 60 x = - 36

x = - \frac{6}{5}

Decimal Notation

x = - 1.2

Solution steps

25 x^{2} + 60 x = - 36

Move

36

to the left side

25 x^{2} + 60 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 25 \cdot 36}{2 \cdot 25}

6 0^{2} - 4 \cdot 25 \cdot 36 = 0

x_{1, 2} = \frac{- 60 \pm 0}{2 \cdot 25}

x = \frac{- 60}{2 \cdot 25}

\frac{- 60}{2 \cdot 25} = - \frac{6}{5}

x = - \frac{6}{5}

The solution to the quadratic equation is:

x = - \frac{6}{5}

(- 2 - 4 i)^{2}

\frac{32 t}{32} = \frac{112}{32}

\frac{1}{3} \cdot 7

2 x^{2} - 21 x y + 27 y^{2}

10 x^{2} + 27 x + 5

What are the solutions to the equation 25x^2+60x=-36 ?
The solutions to the equation 25x^2+60x=-36 are x=-6/5
Find the zeros of 25x^2+60x=-36
The zeros of 25x^2+60x=-36 are x=-6/5