What are the solutions to the equation 3/4 x^2-1/2 x-1/12 =0 ?

The solutions to the equation 3/4 x^2-1/2 x-1/12 =0 are x=(1+sqrt(2))/3 ,x=(1-sqrt(2))/3

Find the zeros of 3/4 x^2-1/2 x-1/12 =0

The zeros of 3/4 x^2-1/2 x-1/12 =0 are x=(1+sqrt(2))/3 ,x=(1-sqrt(2))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{3}{4} x^{2} - \frac{1}{2} x - \frac{1}{12} = 0

x = \frac{1 + 2}{3}, x = \frac{1 - 2}{3}

Decimal Notation

x = 0.80473 \dots, x = - 0.13807 \dots

Solution steps

\frac{3}{4} x^{2} - \frac{1}{2} x - \frac{1}{12} = 0

Find Least Common Multiplier of

4, 2, 12 : 12

Multiply by LCM=

12

\frac{3}{4} x^{2} \cdot 12 - \frac{1}{2} x \cdot 12 - \frac{1}{12} \cdot 12 = 0 \cdot 12

Simplify

9 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 (- 1) = 62

x_{1, 2} = \frac{- ( - 6 ) \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 2}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 6 2}{2 \cdot 9}

x = \frac{- ( - 6 ) + 6 2}{2 \cdot 9} : \frac{1 + 2}{3}

x = \frac{- ( - 6 ) - 6 2}{2 \cdot 9} : \frac{1 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{1 + 2}{3}, x = \frac{1 - 2}{3}

y^{2} - 10 y + 34 = 0

r^{2} - 6 r + 4 = 0

9 a^{2} - 6 ab + b^{2}

2 x^{2} - 5 x

\frac{x ^{2} y ^{5}}{x y ^{4}}

What are the solutions to the equation 3/4 x^2-1/2 x-1/12 =0 ?
The solutions to the equation 3/4 x^2-1/2 x-1/12 =0 are x=(1+sqrt(2))/3 ,x=(1-sqrt(2))/3
Find the zeros of 3/4 x^2-1/2 x-1/12 =0
The zeros of 3/4 x^2-1/2 x-1/12 =0 are x=(1+sqrt(2))/3 ,x=(1-sqrt(2))/3