What is the answer to (2x-7)/7 =(9x-2)/3 ?

The answer to (2x-7)/7 =(9x-2)/3 is x=-7/57

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(2x-7)/7 =(9x-2)/3

\frac{2 x - 7}{7} = \frac{9 x - 2}{3}

x = - \frac{7}{57}

Decimal Notation

x = - 0.12280 \dots

Solution steps

\frac{2 x - 7}{7} = \frac{9 x - 2}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(2 x - 7) \cdot 3 = 7 (9 x - 2)

Expand

(2 x - 7) \cdot 3 : 6 x - 21

Expand

7 (9 x - 2) : 63 x - 14

6 x - 21 = 63 x - 14

Move

21

to the right side

6 x = 63 x + 7

Move

63 x

to the left side

- 57 x = 7

Divide both sides by

- 57

x = - \frac{7}{57}

(\frac{1}{5} x^{3} - 8 y^{2} - 6) - (y^{2} - 5 x^{3} + 10)

567 m^{2} - 343 = 0

- 4 x + 18 x^{5}

(x^{\frac{1}{3}})^{\frac{2}{3}}

3 + \frac{2}{3 + \frac{1}{1 + \frac{1}{4}}}

What is the answer to (2x-7)/7 =(9x-2)/3 ?
The answer to (2x-7)/7 =(9x-2)/3 is x=-7/57
Solve for x: (2x-7)/7 =(9x-2)/3
The solution is x=-7/57