What is (2x^5-6x^2+4x^4y)/(2x) ?

The solution to (2x^5-6x^2+4x^4y)/(2x) is x(x^3-3+2x^2y)

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simplify (2x^5-6x^2+4x^4y)/(2x)

simplify

\frac{2 x ^{5} - 6 x ^{2} + 4 x ^{4} y}{2 x}

x (x^{3} - 3 + 2 x^{2} y)

Solution steps

\frac{2 x ^{5} - 6 x ^{2} + 4 x ^{4} y}{2 x}

Factor

2 x^{5} - 6 x^{2} + 4 x^{4} y : 2 x^{2} (x^{3} - 3 + 2 x^{2} y)

= \frac{2 x ^{2} ( x ^{3} - 3 + 2 x ^{2} y )}{2 x}

Cancel the common factor:

2

= \frac{x ^{2} ( x ^{3} - 3 + 2 x ^{2} y )}{x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{xx ( x ^{3} - 3 + 2 x ^{2} y )}{x}

Cancel the common factor:

x

= x (x^{3} - 3 + 2 x^{2} y)

10 (s - 10) = - 158

y^{2} - 25 x^{4}

- 3 x^{2} - 4 x + 7 = 0

(x - 6) + (x - 4) + (x - 2) + x \leq 148

\frac{n}{4} + \frac{n}{5} = - 18

What is (2x^5-6x^2+4x^4y)/(2x) ?
The solution to (2x^5-6x^2+4x^4y)/(2x) is x(x^3-3+2x^2y)