What are the solutions to the equation -x^2+10x=8 ?

The solutions to the equation -x^2+10x=8 are x=5-sqrt(17),x=5+sqrt(17)

Find the zeros of -x^2+10x=8

The zeros of -x^2+10x=8 are x=5-sqrt(17),x=5+sqrt(17)

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- x^{2} + 10 x = 8

x = 5 - 17, x = 5 + 17

Decimal Notation

x = 0.87689 \dots, x = 9.12310 \dots

Solution steps

- x^{2} + 10 x = 8

Move

8

to the left side

- x^{2} + 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 ( - 1 ) ( - 8 )}{2 ( - 1 )}

1 0^{2} - 4 (- 1) (- 8) = 217

x_{1, 2} = \frac{- 10 \pm 2 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 10 + 2 17}{2 ( - 1 )}, x_{2} = \frac{- 10 - 2 17}{2 ( - 1 )}

x = \frac{- 10 + 2 17}{2 ( - 1 )} : 5 - 17

x = \frac{- 10 - 2 17}{2 ( - 1 )} : 5 + 17

The solutions to the quadratic equation are:

x = 5 - 17, x = 5 + 17

3 n^{2} - 8 n + 5

∣ 3 x + 2 ∣ > 14

x^{2} + 9 x = 70

x^{2} + 1 2^{2} = 1 3^{2}

3 + y = \frac{( 3 y + 9 )}{3}

What are the solutions to the equation -x^2+10x=8 ?
The solutions to the equation -x^2+10x=8 are x=5-sqrt(17),x=5+sqrt(17)
Find the zeros of -x^2+10x=8
The zeros of -x^2+10x=8 are x=5-sqrt(17),x=5+sqrt(17)