What are the solutions to the equation 2t^2-5t=0 ?

The solutions to the equation 2t^2-5t=0 are t= 5/2 ,t=0

Find the zeros of 2t^2-5t=0

The zeros of 2t^2-5t=0 are t= 5/2 ,t=0

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2 t^{2} - 5 t = 0

t = \frac{5}{2}, t = 0

Decimal Notation

t = 2.5, t = 0

Solution steps

2 t^{2} - 5 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 0 = 5

t_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 2}, t_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 2}

t = \frac{- ( - 5 ) + 5}{2 \cdot 2} : \frac{5}{2}

t = \frac{- ( - 5 ) - 5}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

t = \frac{5}{2}, t = 0

\frac{4}{3} + \frac{5}{6}

(x - 3)^{2} + (0 + 5)^{2} = 16

12 x - 39 \leq 9 and - 4 x + 3 < - 6

(x - 1) \cdot (x - 2) \cdot (x + 2) \cdot (x + 3) - 60

\frac{x}{3} = - 48

What are the solutions to the equation 2t^2-5t=0 ?
The solutions to the equation 2t^2-5t=0 are t= 5/2 ,t=0
Find the zeros of 2t^2-5t=0
The zeros of 2t^2-5t=0 are t= 5/2 ,t=0