What are the solutions to the equation 4=-16t^2+24t+4 ?

The solutions to the equation 4=-16t^2+24t+4 are t=0,t= 3/2

Find the zeros of 4=-16t^2+24t+4

The zeros of 4=-16t^2+24t+4 are t=0,t= 3/2

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4 = - 16 t^{2} + 24 t + 4

t = 0, t = \frac{3}{2}

Decimal Notation

t = 0, t = 1.5

Solution steps

4 = - 16 t^{2} + 24 t + 4

Switch sides

- 16 t^{2} + 24 t + 4 = 4

Move

4

to the left side

- 16 t^{2} + 24 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

2 4^{2} - 4 (- 16) \cdot 0 = 24

t_{1, 2} = \frac{- 24 \pm 24}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 24 + 24}{2 ( - 16 )}, t_{2} = \frac{- 24 - 24}{2 ( - 16 )}

t = \frac{- 24 + 24}{2 ( - 16 )} : 0

t = \frac{- 24 - 24}{2 ( - 16 )} : \frac{3}{2}

The solutions to the quadratic equation are:

t = 0, t = \frac{3}{2}

1.1 2^{5}

\frac{3 ^{\frac{2}{3}}}{9 ^{\frac{4}{3}}}

10 x^{2} + 31 x - 14

3 x^{2} - 4 x + 5 = 0

s^{2} + 4 s + 5 = 0

What are the solutions to the equation 4=-16t^2+24t+4 ?
The solutions to the equation 4=-16t^2+24t+4 are t=0,t= 3/2
Find the zeros of 4=-16t^2+24t+4
The zeros of 4=-16t^2+24t+4 are t=0,t= 3/2