What are the solutions to the equation 2x^2+7x=-6 ?

The solutions to the equation 2x^2+7x=-6 are x=-3/2 ,x=-2

Find the zeros of 2x^2+7x=-6

The zeros of 2x^2+7x=-6 are x=-3/2 ,x=-2

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2 x^{2} + 7 x = - 6

x = - \frac{3}{2}, x = - 2

Solution steps

2 x^{2} + 7 x = - 6

Move

6

to the left side

2 x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

7^{2} - 4 \cdot 2 \cdot 6 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 2}, x_{2} = \frac{- 7 - 1}{2 \cdot 2}

x = \frac{- 7 + 1}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 7 - 1}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 2

\frac{2 - 3 i}{1 - 2 i}

24 \cdot 5

z + 0.05 z = 45.15

0 = 5 (2 x - 5) (x + 6)

\frac{3 x - 6}{5} + 1 = 2 x

What are the solutions to the equation 2x^2+7x=-6 ?
The solutions to the equation 2x^2+7x=-6 are x=-3/2 ,x=-2
Find the zeros of 2x^2+7x=-6
The zeros of 2x^2+7x=-6 are x=-3/2 ,x=-2