What is the answer to (3x-2)/4-(2x+5)/3 =(1-x)/6 ?

The answer to (3x-2)/4-(2x+5)/3 =(1-x)/6 is x= 28/3

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(3x-2)/4-(2x+5)/3 =(1-x)/6

\frac{3 x - 2}{4} - \frac{2 x + 5}{3} = \frac{1 - x}{6}

x = \frac{28}{3}

Decimal Notation

x = 9.33333 \dots

Solution steps

\frac{3 x - 2}{4} - \frac{2 x + 5}{3} = \frac{1 - x}{6}

Multiply by LCM

3 (3 x - 2) - 4 (2 x + 5) = 2 (- x + 1)

Expand

3 (3 x - 2) - 4 (2 x + 5) : x - 26

Expand

2 (- x + 1) : - 2 x + 2

x - 26 = - 2 x + 2

Move

26

to the right side

x = - 2 x + 28

Move

2 x

to the left side

3 x = 28

Divide both sides by

3

x = \frac{28}{3}

\frac{3 x + 4}{x - 4} \leq x - 1

2 x^{2} + 5 x + 3 = x^{2} - 8 x - 39

x^{26}

\frac{2}{3} (3 x - 1) \geq \frac{3}{2} (2 x - 3)

What is the answer to (3x-2)/4-(2x+5)/3 =(1-x)/6 ?
The answer to (3x-2)/4-(2x+5)/3 =(1-x)/6 is x= 28/3
Solve for x: (3x-2)/4-(2x+5)/3 =(1-x)/6
The solution is x= 28/3