What is factor (y^4+8y^3+16y^2)-(y^2+8y+16) ?

The solution to factor (y^4+8y^3+16y^2)-(y^2+8y+16) is (y+4)^2(y+1)(y-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor (y^4+8y^3+16y^2)-(y^2+8y+16)

factor

(y^{4} + 8 y^{3} + 16 y^{2}) - (y^{2} + 8 y + 16)

(y + 4)^{2} (y + 1) (y - 1)

Solution steps

(y^{4} + 8 y^{3} + 16 y^{2}) - (y^{2} + 8 y + 16)

Factor

y^{4} + 8 y^{3} + 16 y^{2} : y^{2} (y + 4)^{2}

Factor

y^{2} + 8 y + 16 : (y + 4)^{2}

= y^{2} (y + 4)^{2} - (y + 4)^{2}

Factor out common term

(y + 4)^{2} : (y + 4)^{2} (y^{2} - 1)

= (y + 4)^{2} (y^{2} - 1)

Factor

y^{2} - 1 : (y + 1) (y - 1)

= (y + 4)^{2} (y + 1) (y - 1)

\frac{( 2 g ^{5} ) ^{3}}{( 4 h ^{2} ) ^{3}}

- ln (0.1)

(z + 3)^{2} = - 10

9^{- \frac{3}{2}}

2 \cdot \frac{5}{12}

What is factor (y^4+8y^3+16y^2)-(y^2+8y+16) ?
The solution to factor (y^4+8y^3+16y^2)-(y^2+8y+16) is (y+4)^2(y+1)(y-1)