What are the solutions to the equation x^2+12x+3=0 ?

The solutions to the equation x^2+12x+3=0 are x=-6+sqrt(33),x=-6-sqrt(33)

Find the zeros of x^2+12x+3=0

The zeros of x^2+12x+3=0 are x=-6+sqrt(33),x=-6-sqrt(33)

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x^{2} + 12 x + 3 = 0

x = - 6 + 33, x = - 6 - 33

Decimal

x = - 0.25543 \dots, x = - 11.74456 \dots

Solution steps

x^{2} + 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 3 = 233

x_{1, 2} = \frac{- 12 \pm 2 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 33}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 33}{2 \cdot 1}

x = \frac{- 12 + 2 33}{2 \cdot 1} : - 6 + 33

x = \frac{- 12 - 2 33}{2 \cdot 1} : - 6 - 33

The solutions to the quadratic equation are:

x = - 6 + 33, x = - 6 - 33

\frac{1}{\frac{7}{4}}

25 y^{2} - 4 = 0

7 t = 2 t^{2}

4 5^{- \frac{3}{2}} \cdot 4 5^{2}

325 \cdot 35

What are the solutions to the equation x^2+12x+3=0 ?
The solutions to the equation x^2+12x+3=0 are x=-6+sqrt(33),x=-6-sqrt(33)
Find the zeros of x^2+12x+3=0
The zeros of x^2+12x+3=0 are x=-6+sqrt(33),x=-6-sqrt(33)