What is factor x^4+2x^3-7x^2-20x-12 ?

The solution to factor x^4+2x^3-7x^2-20x-12 is (x+1)(x+2)^2(x-3)

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factor x^4+2x^3-7x^2-20x-12

factor

x^{4} + 2 x^{3} - 7 x^{2} - 20 x - 12

(x + 1) (x + 2)^{2} (x - 3)

Solution steps

x^{4} + 2 x^{3} - 7 x^{2} - 20 x - 12

Use the rational root theorem

= (x + 1) \frac{x ^{4} + 2 x ^{3} - 7 x ^{2} - 20 x - 12}{x + 1}

\frac{x ^{4} + 2 x ^{3} - 7 x ^{2} - 20 x - 12}{x + 1} = x^{3} + x^{2} - 8 x - 12

= (x + 1) (x^{3} + x^{2} - 8 x - 12)

Factor

x^{3} + x^{2} - 8 x - 12 : (x + 2) (x + 2) (x - 3)

= (x + 1) (x + 2) (x + 2) (x - 3)

Apply exponent rule:

aa = a^{2}

(x + 2) (x + 2) = (x + 2)^{2}

= (x + 1) (x + 2)^{2} (x - 3)

6 b < - 18

x^{2} + 10 x + 26 = 0

7^{3}

\frac{u}{5} 2.6 = 3.8

6 4^{- \frac{1}{3}}

What is factor x^4+2x^3-7x^2-20x-12 ?
The solution to factor x^4+2x^3-7x^2-20x-12 is (x+1)(x+2)^2(x-3)