What are the solutions to the equation 4x^2-7=0 ?

The solutions to the equation 4x^2-7=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of 4x^2-7=0

The zeros of 4x^2-7=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} - 7 = 0

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.32287 \dots, x = - 1.32287 \dots

Solution steps

4 x^{2} - 7 = 0

Move

7

to the right side

4 x^{2} = 7

Divide both sides by

4

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

\frac{7 - 11 i}{1 - 3 i}

10 (h + 1) - 4 = 76

42 x^{4} z - 24 x^{5} y^{2} z^{3}

(3 b - 8) + (7 b + 4)

2 - 7

What are the solutions to the equation 4x^2-7=0 ?
The solutions to the equation 4x^2-7=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of 4x^2-7=0
The zeros of 4x^2-7=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2