What are the solutions to the equation x^2+24=11x ?

The solutions to the equation x^2+24=11x are x=8,x=3

Find the zeros of x^2+24=11x

The zeros of x^2+24=11x are x=8,x=3

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x^{2} + 24 = 11 x

x = 8, x = 3

Solution steps

x^{2} + 24 = 11 x

Move

11 x

to the left side

x^{2} + 24 - 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 11 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 24 = 5

x_{1, 2} = \frac{- ( - 11 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 5}{2 \cdot 1}

x = \frac{- ( - 11 ) + 5}{2 \cdot 1} : 8

x = \frac{- ( - 11 ) - 5}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 8, x = 3

\frac{1}{2} (- 1)^{2}

16 x^{2} - 121

16 x^{4} - (y - 2 z)^{2}

2 x < 2

q^{2} + 2 q + 1 = 0

What are the solutions to the equation x^2+24=11x ?
The solutions to the equation x^2+24=11x are x=8,x=3
Find the zeros of x^2+24=11x
The zeros of x^2+24=11x are x=8,x=3