What are the solutions to the equation 4x^2-16x+1=0 ?

The solutions to the equation 4x^2-16x+1=0 are x=(4+sqrt(15))/2 ,x=(4-sqrt(15))/2

Find the zeros of 4x^2-16x+1=0

The zeros of 4x^2-16x+1=0 are x=(4+sqrt(15))/2 ,x=(4-sqrt(15))/2

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4 x^{2} - 16 x + 1 = 0

x = \frac{4 + 15}{2}, x = \frac{4 - 15}{2}

Decimal Notation

x = 3.93649 \dots, x = 0.06350 \dots

Solution steps

4 x^{2} - 16 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 16)^{2} - 4 \cdot 4 \cdot 1 = 415

x_{1, 2} = \frac{- ( - 16 ) \pm 4 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 15}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 4 15}{2 \cdot 4}

x = \frac{- ( - 16 ) + 4 15}{2 \cdot 4} : \frac{4 + 15}{2}

x = \frac{- ( - 16 ) - 4 15}{2 \cdot 4} : \frac{4 - 15}{2}

The solutions to the quadratic equation are:

x = \frac{4 + 15}{2}, x = \frac{4 - 15}{2}

21 \cdot 2

5 x - 6 > 2 x + 15

5 (2 c - 4) + 3 = - 4 c - 10

(x - 8) (x + 9) (7 x + 9) < 0

\frac{x ( x + 4 )}{2} = 96

What are the solutions to the equation 4x^2-16x+1=0 ?
The solutions to the equation 4x^2-16x+1=0 are x=(4+sqrt(15))/2 ,x=(4-sqrt(15))/2
Find the zeros of 4x^2-16x+1=0
The zeros of 4x^2-16x+1=0 are x=(4+sqrt(15))/2 ,x=(4-sqrt(15))/2