What are the solutions to the equation 4x^2+12x+9=25 ?

The solutions to the equation 4x^2+12x+9=25 are x=1,x=-4

Find the zeros of 4x^2+12x+9=25

The zeros of 4x^2+12x+9=25 are x=1,x=-4

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4 x^{2} + 12 x + 9 = 25

x = 1, x = - 4

Solution steps

4 x^{2} + 12 x + 9 = 25

Move

25

to the left side

4 x^{2} + 12 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 16) = 20

x_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 20}{2 \cdot 4}, x_{2} = \frac{- 12 - 20}{2 \cdot 4}

x = \frac{- 12 + 20}{2 \cdot 4} : 1

x = \frac{- 12 - 20}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

\frac{w}{2} = 2

\frac{5 m ^{3} q ^{4}}{m ^{3} q ^{3}}

3 (51 + 6 (5))^{- \frac{1}{2}}

15 x^{2} + 31 x = - 10

∣ 3 x - 6 ∣ > 9

What are the solutions to the equation 4x^2+12x+9=25 ?
The solutions to the equation 4x^2+12x+9=25 are x=1,x=-4
Find the zeros of 4x^2+12x+9=25
The zeros of 4x^2+12x+9=25 are x=1,x=-4