What are the solutions to the equation x^2+x-1=0 ?

The solutions to the equation x^2+x-1=0 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

Find the zeros of x^2+x-1=0

The zeros of x^2+x-1=0 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2

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x^{2} + x - 1 = 0

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

Solution steps

x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 1) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : \frac{- 1 + 5}{2}

x = \frac{- 1 - 5}{2 \cdot 1} : \frac{- 1 - 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{2}, x = \frac{- 1 - 5}{2}

(2 x + 4) (x - 1) + (3 x + 5)^{2} = 3 (2 x + 5)^{2} + x

3 x^{2} + 6 x - 4 = 0

5 - 2 x^{2} = - 3

(x - 1)^{2} = 1

6 k^{2} - 7 k - 20

What are the solutions to the equation x^2+x-1=0 ?
The solutions to the equation x^2+x-1=0 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2
Find the zeros of x^2+x-1=0
The zeros of x^2+x-1=0 are x=(-1+sqrt(5))/2 ,x=(-1-sqrt(5))/2