What is factor a^4-2a^2b^2+b^4 ?

The solution to factor a^4-2a^2b^2+b^4 is (a+b)^2(a-b)^2

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factor a^4-2a^2b^2+b^4

factor

a^{4} - 2 a^{2} b^{2} + b^{4}

(a + b)^{2} (a - b)^{2}

Solution steps

a^{4} - 2 a^{2} b^{2} + b^{4}

Break the expression into groups

= (a^{4} - a^{2} b^{2}) + (- a^{2} b^{2} + b^{4})

Factor out

a^{2}

from

a^{4} - a^{2} b^{2} : a^{2} (a^{2} - b^{2})

Factor out

- b^{2}

from

- a^{2} b^{2} + b^{4} : - b^{2} (a^{2} - b^{2})

= a^{2} (a^{2} - b^{2}) - b^{2} (a^{2} - b^{2})

Factor out common term

a^{2} - b^{2}

= (a^{2} - b^{2}) (a^{2} - b^{2})

Factor

a^{2} - b^{2} : (a + b) (a - b)

= (a + b) (a - b) (a^{2} - b^{2})

Factor

a^{2} - b^{2} : (a + b) (a - b)

= (a + b) (a - b) (a + b) (a - b)

Simplify

= (a + b)^{2} (a - b)^{2}

\frac{x}{14} \geq 1 - \frac{x}{28}

(\frac{1}{16})^{3 x - 4} < 6 4^{x - 1}

(8 r)^{\frac{1}{3}} (2 r^{\frac{1}{2}})

- 7 \cdot - 7

12 b^{3} + 9 b^{2} + 4 b + 3

What is factor a^4-2a^2b^2+b^4 ?
The solution to factor a^4-2a^2b^2+b^4 is (a+b)^2(a-b)^2