What are the solutions to the equation x^2-18x+65=0 ?

The solutions to the equation x^2-18x+65=0 are x=13,x=5

Find the zeros of x^2-18x+65=0

The zeros of x^2-18x+65=0 are x=13,x=5

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x^{2} - 18 x + 65 = 0

x = 13, x = 5

Solution steps

x^{2} - 18 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 65 = 8

x_{1, 2} = \frac{- ( - 18 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 8}{2 \cdot 1}

x = \frac{- ( - 18 ) + 8}{2 \cdot 1} : 13

x = \frac{- ( - 18 ) - 8}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 13, x = 5

(6^{- 4} \cdot 8^{- 7})^{- 9}

- 2 x + 8 + 5 x > 2 x + 1

\frac{5}{40}

- 3 x + 4 = - 8

2 y^{2} - y - 8 = 0

What are the solutions to the equation x^2-18x+65=0 ?
The solutions to the equation x^2-18x+65=0 are x=13,x=5
Find the zeros of x^2-18x+65=0
The zeros of x^2-18x+65=0 are x=13,x=5