What are the solutions to the equation 2+1/4 x^2=5 ?

The solutions to the equation 2+1/4 x^2=5 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 2+1/4 x^2=5

The zeros of 2+1/4 x^2=5 are x=2sqrt(3),x=-2sqrt(3)

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2 + \frac{1}{4} x^{2} = 5

x = 23, x = - 23

Solution steps

2 + \frac{1}{4} x^{2} = 5

Move

2

to the right side

\frac{1}{4} x^{2} = 3

Multiply both sides by

4

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

y^{2} + 5 y - 11 = 0

\frac{x - 17}{( x + 12 ) ^{2} ( x - 29 )} \leq 0

(- 7 + 2 i)^{2}

∣ 4 x ∣ > - 2

4 + \frac{1}{1 - x} \leq \frac{9}{x}

What are the solutions to the equation 2+1/4 x^2=5 ?
The solutions to the equation 2+1/4 x^2=5 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 2+1/4 x^2=5
The zeros of 2+1/4 x^2=5 are x=2sqrt(3),x=-2sqrt(3)