What are the solutions to the equation y^2+5y-11=0 ?

The solutions to the equation y^2+5y-11=0 are y=(-5+sqrt(69))/2 ,y=(-5-sqrt(69))/2

Find the zeros of y^2+5y-11=0

The zeros of y^2+5y-11=0 are y=(-5+sqrt(69))/2 ,y=(-5-sqrt(69))/2

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y^{2} + 5 y - 11 = 0

y = \frac{- 5 + 69}{2}, y = \frac{- 5 - 69}{2}

Solution steps

y^{2} + 5 y - 11 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 11) = 69

y_{1, 2} = \frac{- 5 \pm 69}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 69}{2 \cdot 1}, y_{2} = \frac{- 5 - 69}{2 \cdot 1}

y = \frac{- 5 + 69}{2 \cdot 1} : \frac{- 5 + 69}{2}

y = \frac{- 5 - 69}{2 \cdot 1} : \frac{- 5 - 69}{2}

The solutions to the quadratic equation are:

y = \frac{- 5 + 69}{2}, y = \frac{- 5 - 69}{2}

\frac{x - 17}{( x + 12 ) ^{2} ( x - 29 )} \leq 0

(- 7 + 2 i)^{2}

∣ 4 x ∣ > - 2

4 + \frac{1}{1 - x} \leq \frac{9}{x}

4 a^{2} + 4 ab + b^{2}

What are the solutions to the equation y^2+5y-11=0 ?
The solutions to the equation y^2+5y-11=0 are y=(-5+sqrt(69))/2 ,y=(-5-sqrt(69))/2
Find the zeros of y^2+5y-11=0
The zeros of y^2+5y-11=0 are y=(-5+sqrt(69))/2 ,y=(-5-sqrt(69))/2