What are the solutions to the equation -(x+1)^2=0 ?

The solutions to the equation -(x+1)^2=0 are x=-1

Find the zeros of -(x+1)^2=0

The zeros of -(x+1)^2=0 are x=-1

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- (x + 1)^{2} = 0

x = - 1

Solution steps

- (x + 1)^{2} = 0

Divide both sides by

- 1

(x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 1 = 0 : x = - 1

The solution to the quadratic equation is:

x = - 1

3 y^{2} + 28 y + 9 = 0

2 x^{2} + 50 = 0

4 x^{2} + 9 x + 2 < 0

- x^{2} - 2 x + 1 = 0

ln (x - 2) - 3 ln (2) = 2

What are the solutions to the equation -(x+1)^2=0 ?
The solutions to the equation -(x+1)^2=0 are x=-1
Find the zeros of -(x+1)^2=0
The zeros of -(x+1)^2=0 are x=-1