What is join (-1/(y+1))+2ln(x^2+2) ?

The solution to join (-1/(y+1))+2ln(x^2+2) is (-1+2ln(x^2+2)(y+1))/(y+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

join (-1/(y+1))+2ln(x^2+2)

join

(- \frac{1}{y + 1}) + 2 ln (x^{2} + 2)

\frac{- 1 + 2 ln ( x ^{2} + 2 ) ( y + 1 )}{y + 1}

Solution steps

(- \frac{1}{y + 1}) + 2 ln (x^{2} + 2)

Remove parentheses:

(- a) = - a

= - \frac{1}{y + 1} + 2 ln (x^{2} + 2)

Convert element to fraction:

2 ln (x^{2} + 2) = \frac{2 ln ( x ^{2} + 2 ) ( y + 1 )}{y + 1}

= - \frac{1}{y + 1} + \frac{2 ln ( x ^{2} + 2 ) ( y + 1 )}{y + 1}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 + 2 ln ( x ^{2} + 2 ) ( y + 1 )}{y + 1}

49 x^{2} - 64 = 0

x - 7 = 2 x + 1

12 a^{3} + 8 a^{2} + 15 a + 10

2 - x \geq 0

- 6 x^{2} - 4 x + 4 = 0

What is join (-1/(y+1))+2ln(x^2+2) ?
The solution to join (-1/(y+1))+2ln(x^2+2) is (-1+2ln(x^2+2)(y+1))/(y+1)