What are the solutions to the equation 9q^2-24q+16=0 ?

The solutions to the equation 9q^2-24q+16=0 are q= 4/3

Find the zeros of 9q^2-24q+16=0

The zeros of 9q^2-24q+16=0 are q= 4/3

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9 q^{2} - 24 q + 16 = 0

q = \frac{4}{3}

Decimal Notation

q = 1.33333 \dots

Solution steps

9 q^{2} - 24 q + 16 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 \cdot 16 = 0

q_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 9}

q = \frac{- ( - 24 )}{2 \cdot 9}

\frac{- ( - 24 )}{2 \cdot 9} = \frac{4}{3}

q = \frac{4}{3}

The solution to the quadratic equation is:

q = \frac{4}{3}

ln (\frac{x}{e ^{x}})

15 \cdot 5

9.78 - 6 t \geq 2.34

4 x^{2} - 20 x + 25 = 0

100 a^{2} + 600 a + 500

What are the solutions to the equation 9q^2-24q+16=0 ?
The solutions to the equation 9q^2-24q+16=0 are q= 4/3
Find the zeros of 9q^2-24q+16=0
The zeros of 9q^2-24q+16=0 are q= 4/3